How does the `infer` keyword work in TypeScript?

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In a nutshell

The infer keyword in TypeScript lets you capture and extract a type in the context of conditional type expressions. infer only works when used inside a conditional type expression.

Here’s an example use:

type ExtractReturnType<T extends (...args: any[]) => any> = T extends (
  ...args: any[]
) => infer R
  ? R
  : never

function addNums(a: number, b: number) {
  return a + b
}

function getGreeting() {
  return "Hi there"
}

type AddNumsReturnType = ExtractReturnType<typeof addNums>
type GetGreetingsReturnType = ExtractReturnType<typeof getGreeting>

See this example in the TypeScript playground.

Sources / relevant links

Infer is easier than you think – M a t t P o c k o c k

Tagged: TypeScript

In a nutshell

Sources / relevant links

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